使用SQL实现小计,合计以及排序_MySQL

bitsCN.com--说明：个人学习笔记，实现小计合计显示，分组按BANK_ID+OP_DATE升序排序--测试数据CREATE TABLE #TB(ID VARCHAR(10),BANK_ID VARCHAR(10),OP_DATE VARCHAR(10),OPERATOR_NO VARCHAR(20),AMT DECIMAL(10,2)) INSERT #TB SELECT '1111','001','20121210',1234567,111.00 UNION ALL SELECT '2222','002','20121210',1234567,222.00 UNION ALL SELECT '3333','001','20121112',1234567,250.00 UNION ALL SELECT '4444','002','20121110',1234567,330.00 UNION ALL SELECT '5555','001','20121210',1234567,300.00 UNION ALL SELECT '6666','002','20121112',1234567,150.00 GO--查询SELECT A.ID,A.BANK_ID,A.AMT,B.OP_DATE,B.OPERATOR_NO FROM ((SELECT ID=CASE WHEN GROUPING(BANK_ID)=1 THEN '合计'WHEN GROUPING(ID)=1 THEN '小计'ELSE ID END,BANK_ID,SUM(AMT) AMT,ORDER_SIGN1=GROUPING(BANK_ID),ORDER_SIGN2=BANK_ID,ORDER_SIGN3=GROUPING(ID) FROM #TB GROUP BY BANK_ID,ID WITH ROLLUP HAVING GROUPING(ID)=1 UNION ALL --先得出表的统计，再加上表中的数据SELECT ID,BANK_ID,AMT,ORDER_SIGN1=0,ORDER_SIGN2=BANK_ID,ORDER_SIGN3=0 FROM #TB) A LEFT JOIN --为了显示出OP_DATE、OPERATOR_NO (SELECT ID,OP_DATE,OPERATOR_NO FROM #TB) B ON A.ID = B.ID) ORDER BY ORDER_SIGN1,ORDER_SIGN2,ORDER_SIGN3,OP_DATE GO--删除测试DROP TABLE #TB/*--测试结果ID BANK_ID AMT OP_DATE OPERATOR_NO 3333 001 250.00 20121112 1234567 5555 001 300.00 20121210 1234567 1111 001 111.00 20121210 1234567小计 001 661.00 NULL NULL 4444 002 330.00 20121110 1234567 6666 002 150.00 20121112 1234567 2222 002 222.00 20121210 1234567小计 002 702.00 NULL NULL合计 NULL 1363.00 NULL NULL--*/ bitsCN.com