php生成嵌套json ({"aa": [{"Id": "0",立即学习“PHP免费学习笔记（深入）
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"title": "标题",},{"Id": "1","title": "标题",}],"bb":[{...
},{....
}]}) PHP如何生成这种嵌套的JSON------解决方案--------------------/** Json数据格式化* @param Mixed $data 数据* @param String $indent 缩进字符，默认4个空格* @return JSON*/ function jsonFormat($data, $indent=null){// 对数组中每个元素递归进行urlencode操作，保护中文字符array_walk_recursive($data, 'jsonFormatProtect');// json encode$data = json_encode($data);// 将urlencode的内容进行urldecode$data = urldecode($data);// 缩进处理$ret = '';$pos = 0;$length = strlen($data);$indent = isset($indent)? $indent : ' ';Find JSON Path Online Easily find JSON paths within JSON objects using our intuitive Json Path Finder下载$newline = "";$prevchar = '';$outofquotes = true;for($i=0; $i$char = substr($data, $i, 1);if($char=='"' && $prevchar!='\'){$outofquotes = !$outofquotes;}elseif(($char=='}' ------解决方案-------------------- $char==']') && $outofquotes){$ret .= $newline;$pos --;for($j=0; $j$ret .= $indent;}}$ret .= $char;if(($char==',' ------解决方案-------------------- $char=='{' ------解决方案-------------------- $char=='[') && $outofquotes){$ret .= $newline;if($char=='{' ------解决方案-------------------- $char=='['){$pos ++;}for($j=0; $j$ret .= $indent;}}$prevchar = $char;}return $ret;}/** 将数组元素进行urlencode* @param String $val*/ function jsonFormatProtect(&$val){if($val!==true && $val!==false && $val!==null){$val = urlencode($val);}}header('content-type:application/json;charset=utf8');$arr = array('aa' => array(array('Id' => 0,'title' => '标题'), array( 'Id' => 1, 'title' => '标题' ), ), 'bb' => array( array( 'Id' => 2, 'title' => '标题' ), array( 'Id' => 3, 'title' => '标题' ), ));echo jsonFormat($arr);{ "aa":[ { "Id":"0", "title":"标题" }, { "Id":"1", "title":"标题" } ], "bb":[ { "Id":"2", "title":"标题" }, { "Id":"3", "title":"标题" } ]}